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Gybrisysmemiau7

Gybrisysmemiau7

Answered question

2022-06-26

Solve for α where 0 α 360 , in 1 + 3 tan α sec α = 0

Answer & Explanation

last99erib

last99erib

Beginner2022-06-27Added 19 answers

Squaring both sides is false way because in this case you can get false roots
1 + 3 tan α sec α = 0 1 + 3 sin α cos α 1 cos α = 0 cos α + 3 sin α = 1 1 2 cos α + 3 2 sin α = 1 2 sin 30 cos α + cos 30 sin α = 1 2 sin ( 30 + α ) = 1 2 30 + α = 30 + 360 n , α 1 = 360 n , n = 0 , ± 1 , ± 2 , . . . 30 + α = 180 30 + 360 n α 2 = 120 + 360 n , n = 0 , ± 1 , ± 2 , .

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