Proving that sin &#x2061;<!-- ⁡ --> &#x03B1;<!-- α --> +

Ximena Skinner

Ximena Skinner

Answered question

2022-07-13

Proving that sin α + sin β cos α + cos β = tan ( α + β 2 )

Answer & Explanation

Charlee Gentry

Charlee Gentry

Beginner2022-07-14Added 19 answers

sin α + sin β = 2 sin ( α + β 2 ) cos ( α β 2 ) .
cos α + cos β = 2 cos ( α + β 2 ) cos ( α β 2 ) .
So, you get the conclusion.
Wade Bullock

Wade Bullock

Beginner2022-07-15Added 5 answers

Another approach:
Put: tan ( α / 2 ) = a and tan ( β / 2 ) = b
Than:
sin α = 2 a 1 + a 2 cos α = 1 a 2 1 + a 2
sin β = 2 b 1 + b 2 cos β = 1 b 2 1 + b 2
and:
sin α + sin β cos α + cos β = 2 a ( 1 + b 2 ) + 2 b ( 1 + a 2 ) ( 1 a 2 ) ( 1 + b 2 ) + ( 1 b 2 ) ( 1 + a 2 )
that, after a bit of algebra, becomes:
= a + b 1 a b = tan α / 2 + tan β / 2 1 tan α / 2 tan β / 2 = tan ( α + β 2 )

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