Prove cos &#x2061;<!-- ⁡ --> 2 <mrow class="MJX-TeXAtom-ORD"> &#x3B1; </mrow>

Crystal Wheeler

Crystal Wheeler

Answered question

2022-07-15

Prove cos 2 α = 2 sin 2 β + 4 cos ( α + β ) sin α sin β + cos 2 ( α + β )

Answer & Explanation

trantegisis

trantegisis

Beginner2022-07-16Added 20 answers

P = 2 sin 2 β + 4 cos ( α + β ) sin α sin β + cos 2 ( α + β )
We have that:
2 cos ( α + β ) sin ( β ) = sin ( α + 2 β ) sin ( α )
so,
4 cos ( α + β ) sin ( β ) sin ( α ) = 2 sin ( α + 2 β ) sin ( α ) 2 sin 2 ( α )
but,
2 sin ( α + 2 β ) sin ( α ) = cos ( 2 β ) cos [ 2 ( α + β ) ]
then
P = 2 sin 2 β + cos ( 2 β ) cos [ 2 ( α + β ) ] 2 sin 2 ( α ) + cos [ 2 ( α + β ) ] P = 1 cos ( 2 β ) + cos ( 2 β ) 2 sin 2 ( α ) = cos ( 2 α )

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?