Find the distance between a point and a plane. I have been trying to solve this exercice and I would like to know if my solution is correct or not ? Point is P=(1,7,4) Plane has an equation : 5x+3y+z=8 I have taken a random point on the plane Q=(1,1,0) vec(PQ) = <0,-6,-4> Normal to the plane is : vec(N) = <5,3,1>

okunyangae8

okunyangae8

Answered question

2022-08-12

I have been trying to solve this exercice and I would like to know if my solution is correct or not ?
Point is P = ( 1 , 7 , 4 )
Plane has an equation : 5 x + 3 y + z = 8
I have taken a random point on the plane Q=(1,1,0)
P Q =< 0 , 6 , 4 >
Normal to the plane is :
N =< 5 , 3 , 1 >
(by reading the coefficients of the plane's equation)
D i s t a n c e = | P Q N | N | | = 0 18 4 5 ² + 3 ² + 1 ² = 22 35

Answer & Explanation

Brogan Navarro

Brogan Navarro

Beginner2022-08-13Added 24 answers

Your reasoning is correct, however the calculation of the vector P Q is not correct.
P Q = Q P = ( 0 , 6 , 4 ). Using this vector you will end up with the fraction 22 35
(Don't forget the absolute value.)

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