The given is r(t)=3/2 t^2 i−4tj+1/2 t^3 k Taking the first two derivatives: r′(t)=3ti−4j+3/2 t^2 k r′′(t)=3i+3tk Taking the dot product of r′(t) * r′′(t) 9t+9/2 t^2 And now the cross product of r′(t)Xr′′(t) -12ti+9/2 t^2 j+12k I know I did the dot product correct but the website we are using says its wrong, I then did the cross product but it also says that is wrong as well.

chemicars8

chemicars8

Open question

2022-08-22

The given is
r ( t ) = 3 2 t 2 i i 4 t j j + 1 2 t 3 k k
Taking the first two derivatives:
r ( t ) = 3 t i i 4 j j + 3 2 t 2 k k
r ( t ) = 3 i i + 3 t k k
Taking the dot product of r ( t ) r ( t )
9 t + 9 2 t 2
And now the cross product of r ( t ) X r ( t ) 12 t i i + 9 2 t 2 j j + 12 k k
then did the cross product but it also says that is wrong as well.

Answer & Explanation

Jaydon Villanueva

Jaydon Villanueva

Beginner2022-08-23Added 7 answers

You should check your calculations. For the first thing, r ( t ) r ( t ) = 9 t + 9 2 t 3 . Indeed, it looks to me like you made a mistake in multiplying the k components together.
As for the cross product: it looks like you made the common mistake of not putting a "-" before the j term. It becomes:
r ( t ) × r ( t ) = 12 t i 9 t 2 2 j + 12 k .

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