I understand how to solve this problem: i.e. take the unit vector of a, then multiply by our given magnitude (in this case sqrt2) which gives: (sqrt2)/(5)(3i+4j). I'm confused as to what the mathematical logic behind this, how would you explain why we're doing this process?

hotonglamoz

hotonglamoz

Answered question

2022-09-22

I understand how to solve this problem: i.e. take the unit vector of a, then multiply by our given magnitude (in this case 2 ) which gives: 2 5 ( 3 i + 4 j )
I'm confused as to what the mathematical logic behind this, how would you explain why we're doing this process?

Answer & Explanation

Kody Gates

Kody Gates

Beginner2022-09-23Added 5 answers

Magnitude of b = i j | b | = 1 2 + ( 1 ) 2 = 2
Unit vector parallel to a = 3 i + 4 j a ^ = a | a | = 3 i + 4 j 3 2 + 4 2 = 1 5 ( 3 i + 4 j )
The required vector with magnitude equal to that of b & directed along a :
| b | a ^ = 2 1 5 ( 3 i + 4 j ) = 2 5 ( 3 i + 4 j )
Hagman7v

Hagman7v

Beginner2022-09-24Added 3 answers

The solution that you mentiond was this: b a a = b a a. Since it is a times a positive number, it has the same direction as a. Besides,
b a a = b a a = b ,
as you wanted.

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