Let g(x,y)=ln[\sin(x+a/sqrt(y))], where a is a constant. Find dg/dx and dg/dy

Hagman7v

Hagman7v

Answered question

2022-09-23

Let g ( x , y ) = ln [ sin ( x + a y ) ], where a is a constant. Find d g d x and d g d y .

Answer & Explanation

ticotaku86

ticotaku86

Beginner2022-09-24Added 12 answers

g ( x , y ) = ln [ sin ( x + a y ) ] d g d x , d g d y = ? d g d x = d ln [ sin ( x + a y ) ] d x
Differentiate with respect to x.
As we know d ( ln x ) d x = 1 x and  d ( sin x ) d x = cos x
so, by applying chain rule
d g d x = 1 sin ( x + a y ) cos ( x + a y ) 1 + a y ( 1 + a y ) cot ( x + a y ) cos x sin x = cot x
Now,
Similiarly we find d g d y by chain rule as differentiate it with respect to y.
we get d ln [ sin ( x + a y ) ] d y
we know, d ( ln y ) d y = 1 y and  d ( sin y ) d y = cos y and  d ( 1 y ) d y = 1 2 y 3 / 2 So,  d g d y = 1 sin ( x + a y ) cos ( x + a y ) ( x + a ) 2 y 3 / 2 = cos ( x + a y ) sin x + a y d g d y = ( x + a ) 2 y 3 cot ( x + a y )

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