For A,B,C,D in bbbF^(n xx n), show that det((A,C),(B,D))=det A det D−det B det C

timberwuf8r

timberwuf8r

Answered question

2022-09-06

For A , B , C , D F n × n , show that det ( A B C D ) = det A det D det B det C

Answer & Explanation

Cody Petty

Cody Petty

Beginner2022-09-07Added 6 answers

If we have
det ( A B 0 D ) = det ( A ) det ( D )
Similarly one can trivially write
det ( A 0 C D ) = det ( A ) det ( D )
Now observe that
( I 0 C A 1 I ) ( A B C D ) = ( A B 0 D C A 1 B )
Thus one can write that
det ( I ) det ( I ) det ( A B C D ) = det ( A ) det ( D C A 1 B )
jamstavajo

jamstavajo

Beginner2022-09-08Added 2 answers

The correct result is
det [ A B C D ] = det ( A D B C )

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