If A,B,C,D be 4 points in a space and satisfy |vec(AB)|=3,|vec(BC)|=7,|vec(CD)|=11,|vec(DA)|=9, Then value of vec(AC) * vec(BD)=

mriteyl

mriteyl

Answered question

2022-09-07

If A,B,C,D be 4 points in a space and satisfy | A B | = 3 , | B C | = 7 , | C D | = 11 , | D A | = 9 , Then value of A C B D =
what i try
Let position vector of A ( 0 ) , B ( b ) , C ( c ) , D ( d )
Then A C B D = | A C | | B D | cos θ
where θ ia an angle between A C and B D
How do i solve it help me please

Answer & Explanation

Abigayle Lynn

Abigayle Lynn

Beginner2022-09-08Added 12 answers

Use
A C = A B C B = A D C D
B D = A D A B = C D C B
to evaluate A C B D
2 A C B D = A C ( A D A B ) + A C ( C D C B )
= A C ( A D + C D ) A C ( A B + C B )
= ( A D C D ) ( A D + C D ) ( A B C B ) ( A B + C B )
= | A D | 2 | C D | 2 | A B | 2 + | C B | 2
= 9 2 11 2 3 2 + 7 2 = 0
Litzy Downs

Litzy Downs

Beginner2022-09-09Added 1 answers

There was actually a sign mistake in the last step of my calculation, now it's fixed.
After giving it a thought, I noticed that
3 2 + 11 2 = A B 2 + C D 2 = B C 2 + A D 2 = 7 2 + 9 2
thus
A B 2 A D 2 = B C 2 C D 2
this implies that
( A B + A D ) ( A B A D ) = ( B C + C D ) ( B C C D )
and now by rewriting the expression we end up with
( A B + A D ) ( D B ) = ( B C C D ) B D ( A B A D ) ( B D ) = ( B C C D ) B D 0 = ( B C C D + A B + A D ) B D 0 = ( A B + B C + A D + D C ) B D 0 = 2 A C B D
which gives the result.
Thi can analogously be obtained from
A B 2 B C 2 = A D 2 C D 2

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