s2vunov

2022-09-07

The roots of the quadratic equation $a{x}^{2}-16x+25$ and $2-mi$, where $m>0$. Compute the sum of $a+m$

lascosasdeali3v

Beginner2022-09-08Added 10 answers

The roots are given by the quadratic formula:

$x=\frac{16\pm \sqrt{{16}^{2}-4\ast 25\ast a}}{2a}$

We know that the real part of the roots will be 2, so $\frac{16}{2a}=2$, and $a=4$. So we can plug that back into the quadratic formula.

$x=\frac{16\pm \sqrt{{16}^{2}-4\ast 25\ast 4}}{2\ast 4}$

and solve for your roots.

$x=\frac{16\pm \sqrt{{16}^{2}-4\ast 25\ast a}}{2a}$

We know that the real part of the roots will be 2, so $\frac{16}{2a}=2$, and $a=4$. So we can plug that back into the quadratic formula.

$x=\frac{16\pm \sqrt{{16}^{2}-4\ast 25\ast 4}}{2\ast 4}$

and solve for your roots.

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