Factorise f(x)=x^5-x into a product of irreducibles in ZZ_5[x]

Lara Cortez

Lara Cortez

Answered question

2022-10-20

Factorise f ( x ) = x 5 x into a product of irreducibles in Z 5 [ x ]

Answer & Explanation

silenthunter440

silenthunter440

Beginner2022-10-21Added 19 answers

f ( x ) = x ( x 1 ) ( x 3 + x 2 + x + 1 ) = x ( x 1 ) ( x + 1 ) ( x 2 + 1 )
( x + a ) ( x + b ) = x 2 + ( a + b ) x + a b = x 2 + 1
So a + b = 0 ( 5 ) and a b = 1 ( 5 ) Hence a = 2 and b = 3
f ( x ) = x ( x 1 ) ( x + 1 ) ( x + 2 ) ( x + 3 )

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