Let x, y, z, t are real numbers. x+y+z+t=6 and sqrt(1−x^2)+sqrt(4−y^2)+sqrt(9−z^2)+sqrt(16−t^2)=8 Find each value of them as a number.

oopsteekwe

oopsteekwe

Answered question

2022-11-01

Let x, y, z, t are real numbers. x+y+z+t=6 and 1 x 2 + 4 y 2 + 9 z 2 + 16 t 2 = 8 Find each value of them as a number.

Answer & Explanation

Davin Meyer

Davin Meyer

Beginner2022-11-02Added 13 answers

Consider following 4 vectors in R 2 ,
a = ( x , 1 x 2 ) , b = ( y , 4 y 2 ) , c = ( z , 9 z 2 )  and  d = ( t , 16 t 2 )
We have | a | = 1 , | b | = 2 , | c | = 3 and | d | = 4. The given conditions tell us
a + b + c + d = ( 6 , 8 ) | a + b + c + d | = | ( 6 , 8 ) | = 10 = | a | + | b | + | c | + | d |
By triangle inequality, this is possible only when the 4 vectors are pointing in same direction. This implies
x : y : z : t = | a | : | b | : | c | : | d | = 1 : 2 : 3 : 4 ( x , y , z , t ) = ( 3 5 , 6 5 , 9 5 , 12 5 )
podvelkaj8

podvelkaj8

Beginner2022-11-03Added 3 answers

By AM-GM
8 = ( 1 x ) ( 1 + x ) + ( 2 y ) ( 2 + y ) + ( 3 z ) ( 3 + z ) + ( 4 t ) ( 4 + t ) =
= 2 ( 1 x ) 1 + x 4 + 2 ( 2 y ) 2 + y 4 + 2 ( 3 z ) 3 + z 4 + 2 ( 4 t ) 4 + t 4
1 x + 1 + x 4 + 2 y + 2 + y 4 + 3 z + 3 + z 4 + 4 t + 4 + t 4 = 8 ,
which gives
1 x = 1 + x 4 ,
2 y = 2 + y 4 ,
3 z = 3 + z 4
and
4 t = 4 + t 4
or
( x , y , z , t ) = ( 3 5 , 6 5 , 9 5 , 12 5 ) .

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