Prove that: (vec(u) xx vec(v)) xx vec(w)=(vec(w) * vec(u)) vec(v) −(vec(v) * vec(w)) vec(u)
I'm trying to solve this question, and my only thoughts of proving it is just to substitute vec(u)=(u_1,u_2,u_3) and same for all vectors and open it up following the dot and cross product rules.
But I was wondering if there's another creative way other than the straight forward way that I'm thinking about.
Rigoberto Drake
Answered question
2022-11-19
Prove that: I'm trying to solve this question, and my only thoughts of proving it is just to substitute and same for all vectors and open it up following the dot and cross product rules. But I was wondering if there's another creative way other than the straight forward way that I'm thinking about. Appreciate any help
Answer & Explanation
Maffei2el
Beginner2022-11-20Added 20 answers
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The "creative" way first notes anything orthogonal to is a linear combination of . Since , the coefficient of needs to be bilinear in . Further, it needs to be a scalr invariant under rotations, so it must be a multiple of . We can treat the coefficient similarly, making it a multiple of . By -antisymmetry, some k satisfies
You can fix k=1 with e.g. making both sides
Aryanna Fisher
Beginner2022-11-21Added 6 answers
The vector (u x v)xw is perpendicular to uxv , therefore it's in the same plane as the vectors u and v. Therefore , (u x v)xw can be expressed as a linear combination of the vectors u and v because it's coplanar with both the vectors . Now , let (u x v)xw = l.u + m.v ,...(1) where l , m are constants . Taking scalar product with w both sides , 0 = l(w.u) + m(w.v) Solving , we get , l/(w.u) = -m/(w.v) = k(say) , where k is a constant . Therefore , l=k(w.u) and m=-k(w.v) Putting these values in equation 1 , we get (u x v)xw= k{(w.u)v - (w.v)u} And more generally , (u x v)xw = (w.u)v -(w.v)u