1−cos(x)/x herefore, the limit is

Jaden Bird

Jaden Bird

Answered question

2022-11-28

1 cos ( x ) x herefore, the limit is

Answer & Explanation

ysik92ASw

ysik92ASw

Beginner2022-11-29Added 13 answers

Firstly is to multiple the conjugate of the numerator. Secondly is to use 1 cos 2 ( x ) to get sin 2 ( x ).
lim x 0 1 cos x x 1 + cos x 1 + cos x = lim x 0 1 cos 2 x x + cos x = lim x 0 sin 2 x x + cos x = lim x 0 ( sin x x ) ( sin x 1 + cos x ) = 1 0 = 0

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