E=(t)^0(m)^1(c)^2 . Here, m = mass of the body. c = velocity of light. Is t the time?

hommequidort0h

hommequidort0h

Answered question

2022-09-16

E = ( t ) 0 ( m ) 1 ( c ) 2 . Here, m = mass of the body. c = velocity of light. Is t the time?

Answer & Explanation

edytorialkp

edytorialkp

Beginner2022-09-17Added 10 answers

f we're trying to guess an equation for the energy we might guess it's some function of mass, the speed of light and time, so we can write a general equation as:
E = t α m β c γ
In dimensional analysis we check to see that the units are consistent, i.e. the units are the same on the left and right sides of the equation. To work out the units of energy we note that energy is force times distance, and force is mass times acceleration and acceleration is distance/time 2 . So the units of energy are M L 2 T 2 . So if we just write down the units for our equation we get:
M L 2 T 2 = T α M β ( L T 1 ) γ
The exponents of M, L and T must match on both sides, so we get three simultaneous equations:
1 = β 2 = γ 2 = α γ
And obviously to satisfy these equations α must be zero. So, if our initial assumption was correct the equation must be:
E = t 0 m c 2
and since anything to the power zero is unity this gives us the usual equation for mass-energy equivalence.

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