A rational function f in n variables is a ratio of 2 polynomials,
where q is not identically 0. The function is called symmetric if
for any permutation of .
Let F denote the field of rational functions and S denote the subfield of symmetric rational functions. Suppose the coefficients of polynomials are all real numbers.
Show that F=S(h), where . In other words, show that h generates F as a field extension of S.
Attempt at Solution:
1.Can't seem to get very far with this one. I know that F is a finite extension of S of degree n! and the Galois group of the extension is .
2.Using h and the 1st symmetric function , we see that .
3.Can't seem to find a good way to use the other symmetric functions .