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Algebra II

How would you solve for $x$ in $7^{x} = 5^{x - 4}$
How would you be able to make these the same base? I tried to put it into a base $10$ formula, but it ended up making $x = 0$

res2bfitjq 2022-05-19

I was asked to dismantle this rational function by parts and wanted to know if I did it right.The function is:
$\frac{x^{5} - x + 3}{x (x - 2)^{3} (x^{2} + 2 x + 2)}$
What I did is:
$\frac{A}{X} + \frac{B}{(x - 2)} + \frac{C}{(x - 2)^{2}} + \frac{D}{(x - 2)^{3}} + \frac{G X + C}{x^{2} + 2 x + 2}$

Aditya Erickson 2022-05-19

Why must the base of a logarithm be a positive real number not equal to 1?
and why must x be positive?
Thanks.

brendijadq 2022-05-19

simplify the following logarithm and roots expression
please , I need help to solve this problem Can anyone solve it simplify the following
$\log \sqrt[4]{729 \sqrt[3]{\frac{1}{39} \sqrt{{(\frac{1}{27})}^{4}}}}$
thank in advance to all

Cara Duke 2022-05-19

Under what conditions a rational function has bounded derivative?
This question arise to me when considering the following theorem:
If $f \in C^{1} (I, R)$ where I is an interval then:
f is globally lipschitz
$⟺ \exists L \geq 0. \forall t \in I . | f^{'} (t) | \leq L$
So taking rational function $f (x) = \frac{p (x)}{q (x)}$ we have $f^{'} (x) = \frac{p^{'} (x) q (x) - p (x) q^{'} (x)}{q (x)^{2}}$ .
My view
I think I should assume that $f : R \to R$ so that $\forall x \in R . q^{'} (x) \neq 0$ (however this doesn't seem to be necesary). And then perhaps a condition on the degree guarantees boundedness...

kromo8hdcd 2022-05-19

What is the value of s such that 20s+4=11s-2?

Blaine Stein 2022-05-19

Calculate the value of x such that 15-16x=11x+4.

adocidasiaqxm 2022-05-19

Find the value of x such that 18x=14.

hard12bb30crg 2022-05-19

Calculate the value of x such that -16x equals 19.

Jaeden Weaver 2022-05-19

Simplify: $(6 + 11 i) - (\frac{3}{4} + \frac{i}{5})$ .

Nubydayclellaumvcd 2022-05-19

Subtract $7 + \frac{5 i}{2}$ from $\frac{2}{5} + 6 i$ .

vilitatelp014 2022-05-19

Calculate $(7 + 9 i) - (\frac{5}{7} + \frac{5 i}{3})$ .

Marco Villanueva 2022-05-19

Compute $(\frac{2}{3} + \frac{6 i}{13}) - (6 + 15 i)$ .

Azzalictpdv 2022-05-19

Subtract 4+10i from $\frac{2}{7} + \frac{2 i}{11}$ .

Marissa Singh 2022-05-19

Compute $(\frac{3}{2} + \frac{14 i}{13}) - (3 + 14 i)$

garcialdaria2zky1 2022-05-19

Calculate $(\frac{11}{4} + 2 i) - (14 + \frac{3 i}{8})$ .

Marissa Singh 2022-05-19

Calculate $(\frac{2}{7} + \frac{3 i}{7}) + (7 + 13 i)$ .

The majority of Algebra 2 homework will be almost the same for college students these days since the only changes will relate to a practical application like business solutions, financial challenges, and certain problems where formulas and concepts are applicable. Looking for Algebra 2 answers, you will find some solutions below that are most likely to answer your Algebra 2 problems and answers. If you’re a high-school learner, there are Algebra 2 questions for you as well with provided solutions. The most important is to share your instructions and read through examples that address various Algebra 2 questions and answers.

Algebra II

How would you solve for $x$ in $7^{x} = 5^{x - 4}$
How would you be able to make these the same base? I tried to put it into a base $10$ formula, but it ended up making $x = 0$

I was asked to dismantle this rational function by parts and wanted to know if I did it right.The function is:
$\frac{x^{5} - x + 3}{x (x - 2)^{3} (x^{2} + 2 x + 2)}$
What I did is:
$\frac{A}{X} + \frac{B}{(x - 2)} + \frac{C}{(x - 2)^{2}} + \frac{D}{(x - 2)^{3}} + \frac{G X + C}{x^{2} + 2 x + 2}$

Why must the base of a logarithm be a positive real number not equal to 1?
and why must x be positive?
Thanks.

simplify the following logarithm and roots expression
please , I need help to solve this problem Can anyone solve it simplify the following
$\log \sqrt[4]{729 \sqrt[3]{\frac{1}{39} \sqrt{{(\frac{1}{27})}^{4}}}}$
thank in advance to all

What is the value of s such that 20s+4=11s-2?

Calculate the value of x such that 15-16x=11x+4.

Solve the equation 11-18u=0.

Solve for a: 13a=3.

Find the value of x such that 18x=14.

Solve -21x=16 for x.

Calculate the value of x such that -16x equals 19.

Simplify: $(6 + 11 i) - (\frac{3}{4} + \frac{i}{5})$ .

Subtract $7 + \frac{5 i}{2}$ from $\frac{2}{5} + 6 i$ .

Calculate $(7 + 9 i) - (\frac{5}{7} + \frac{5 i}{3})$ .

Compute $(\frac{2}{3} + \frac{6 i}{13}) - (6 + 15 i)$ .

Subtract 4+10i from $\frac{2}{7} + \frac{2 i}{11}$ .

Compute $(\frac{3}{2} + \frac{14 i}{13}) - (3 + 14 i)$

Calculate $(\frac{11}{4} + 2 i) - (14 + \frac{3 i}{8})$ .

Calculate $(\frac{2}{7} + \frac{3 i}{7}) + (7 + 13 i)$ .

Expert Answers to Algebra 2 Problems