A shopper in a supermarket pushes a cart with a force of 35 N directed

Paloma Owens

Paloma Owens

Answered question

2023-03-30

A consumer in a grocery store pushes a cart with a force of 35 N directed at an angle of 25 below the horizontal. The force is just enough to overcome various frictional forces, so the cart moves at a steady pace. Find the work done by the shopper as she moves down a 50.0m length aisle.

??

Answer & Explanation

idoless0069w7r

idoless0069w7r

Beginner2023-03-31Added 6 answers

To find the work done by the shopper as she moves down the aisle, we can use the formula for work:
W=F·d·cos(θ)
Where:
W is the work done,
F is the applied force,
d is the distance, and
θ is the angle between the force and the direction of motion.
In this case, the applied force is 35 N and the distance is 50.0 m. The angle between the force and the direction of motion is 25 degrees below the horizontal.
Substituting these values into the formula, we get:
W=35N·50.0m·cos(25)
To calculate the cosine of 25 degrees, we need to convert the angle to radians. We know that π radians is equal to 180 degrees, so we can convert 25 degrees to radians by multiplying it by π180:
W=35N·50.0m·cos(25π180)
Now, we can calculate the cosine of the angle:
W=35N·50.0m·cos(25π180)35N·50.0m·0.90631
Calculating the product of the force, distance, and cosine value:
W1581.55N·m1581.55J
Finally, we can convert the work from joules to kilojoules by dividing by 1000:
W1581.55J10001.58kJ
Therefore, the work done by the shopper as she moves down the 50.0 m length aisle is approximately 1.58kJ, which can be represented as Wman=1.58kJ.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?