simplify (sinx/(1+sinx)) + ((1+sinx)/cosx)

teddytinotendak

teddytinotendak

Answered question

2022-07-18

simplify (sinx/(1+sinx)) + ((1+sinx)/cosx)

Answer & Explanation

Eliza Beth13

Eliza Beth13

Skilled2023-05-23Added 130 answers

To simplify the expression sin(x)1+sin(x)+1+sin(x)cos(x), we'll start by finding a common denominator for the two fractions.
sin(x)1+sin(x)+1+sin(x)cos(x)
Let's find the common denominator for the two fractions, which is cos(x)(1+sin(x)).
sin(x)·cos(x)cos(x)(1+sin(x))+(1+sin(x))·(1+sin(x))cos(x)(1+sin(x))
Now, we can combine the fractions over the common denominator.
sin(x)·cos(x)+(1+sin(x))2cos(x)(1+sin(x))
Expanding (1+sin(x))2 gives us:
sin(x)·cos(x)+1+2sin(x)+sin2(x)cos(x)(1+sin(x))
Simplifying the expression further, we have:
sin(x)·cos(x)+1+2sin(x)+sin2(x)cos(x)+sin(x)·cos(x)
Now, let's simplify the numerator. Combining like terms, we get:
sin2(x)+2sin(x)+sin(x)·cos(x)+1cos(x)+sin(x)·cos(x)
Grouping the terms with sin(x) together:
sin2(x)+3sin(x)+1cos(x)+sin(x)·cos(x)
Factoring the numerator:
(sin(x)+1)(sin(x)+1)cos(x)+sin(x)·cos(x)
Simplifying the expression even further:
(sin(x)+1)2cos(x)+sin(x)·cos(x)
Therefore, the simplified form of the expression sin(x)1+sin(x)+1+sin(x)cos(x) is (sin(x)+1)2cos(x)+sin(x)·cos(x).

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