How to solve 8(4-x)=7x+2?

Whothoromapyfb

Whothoromapyfb

Answered question

2022-12-25

How to solve 8(4x)=7x+2?

Answer & Explanation

mercerizoblx

mercerizoblx

Beginner2022-12-26Added 7 answers

We have equation
\(\displaystyle{8}{\left({4}-{x}\right)}={7}{x}+{2}\)
Distributive property "subtraction variant": applied concept
\(\displaystyle{a}{\left({b}-{c}\right)}={a}{\left({b}\right)}-{a}{\left({c}\right)}\)
calculations
\(\displaystyle{8}{\left({4}-{x}\right)}={7}{x}+{2}\)
distributive property \(\displaystyle\ \text{ }\ {8}{\left({4}\right)}-{8}{\left({x}\right)}={7}{x}+{2}\)
simplify \(\displaystyle\ \text{ }\ {32}-{8}{x}={7}{x}+{2}\)
8x both sides of that PSK" "32\cancel(-8x)\cancel(\color(indianred)(+8x))=7x+2\color(indianred)(+8x)ZSK
simplify \(\displaystyle\ \text{ }\ {32}={15}{x}+{2}\)
subtract 2 from both sides PSK" "32\color(teal)(-2)=15x\cancel(+2)\cancel(\color(teal)(-2))ZSK
simplify \(\displaystyle{30}={15}{x}\)
divide both sides by 15 \(\displaystyle\ \text{ }\ \frac{{30}}{{\color{mar\inftyn}{{15}}}}=\frac{{\cancel{{{15}}}{x}}}{\cancel{{{\color{mar\inftyn}{{15}}}}}}\)
simplify \(\displaystyle{x}=\frac{{30}}{{15}}={2}\)

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