Wierzycaz
2020-11-06
The product of two consecutive positive integers is 1,332. Describe how to create and solve a quadratic equation to determine the greater integer's value.
Gennenzip
Skilled2020-11-07Added 96 answers
Let x be the smaller of the consecutive positive integers. Consecutive integers are 1 away from each other so the larger integer must be x+1.
The product of the two consecutive positive integers is then x(x+1) so if the product is 1,332, then x(x+1)=1,332.
To solve this quadratic equation, first distribute the term with x to get
Subtracting 1,332 on both sides then gives
To factor , find two numbers that when multiplied together equal −1,332 since the constant is −1,332 and add to 11 since the middle term has a coefficient of 11. Those two numbers are 37 and −36 since 37(−36)=−1,332 and 37+(−36)=1.
The factored form of the quadratic equation is then (x+37)(x−36)=0.
Set each element to 0 and then resolve each linear equation for x.
Setting the first factor equal to 0 gives x+37=0. Subtracting 37 on both sides gives x=−37. The integers must be positive though so the smaller integer cannot be −37.
Setting the second factor equal to 0 gives x−36=0. Addin 36 on both sides gives x=36.
The smaller integer is then 36 and the larger integer is x+1=36+1=37.
2022-01-19
The numbers can be written as x and x + 1. Set the product of the numbers equal to 1,332 to get x(x + 1) = 1,332. You can solve the quadratic equation by using the quadratic formula, completing the square, or factoring. When you solve the quadratic equation, you find that x = –37 and 36. Since the question asked for positive integers, the only viable solution is x = 36. To solve for the larger integer, you add 1 to 36 to get an answer of 37.
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