For f(x)=24−2x, how do you find f(2) and x such that f(x)=10?

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hemelbol26w · Accepted Answer

To calculate f(2), enter x=2 in place of f(x).
\(\displaystyle{f{{\left({\color{red}{{2}}}\right)}}}={24}-{\left({2}\times{\color{red}{{2}}}\right)}\)
\(\displaystyle{\color{white}{{f{{\left({2}\right)}}}}}={24}-{4}\)
\(\displaystyle{\color{white}{{f{{\left({2}\right)}}}}}={20}\)
\(\displaystyle\text{given}{f{{\left({x}\right)}}}={24}-{2}{x}\ \text{ and }\ {f{{\left({x}\right)}}}={10}\)
\(\displaystyle\text{then we can equate the right sides}\)
\(\displaystyle\Rightarrow{24}-{2}{x}={10}\)
\(\displaystyle\text{subtract 24 from both sides}\)
\(\displaystyle\cancel{{{24}}}\cancel{{-{24}}}-{2}{x}={10}-{24}\)
\(\displaystyle\Rightarrow-{2}{x}=-{14}\)
\(\displaystyle\text{divide both sides by - 2}\)
\(\displaystyle\frac{{\cancel{{-{2}}}{x}}}{\cancel{{-{2}}}}=\frac{{-{14}}}{{-{2}}}\)
\(\displaystyle\Rightarrow{x}={7}\)

For f(x)=24-2x, how do you find f(2) and x such that f(x)=10?

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