How many real number solutions? -7x^2+6x+3=0

gwestaikd4

gwestaikd4

Answered question

2022-12-29

How many real number solutions?
7x2+6x+3=0

Answer & Explanation

estossavafjg

estossavafjg

Beginner2022-12-30Added 3 answers

7x2+6x+3
Utilize the discriminant to resolve this:
ax2+bx+c
discriminant =b24ac
=62473
=36(84)
=120
Raina Cole

Raina Cole

Beginner2022-12-31Added 1 answers

The number of actual solutions to a quadratic equation of the form, y=ax2+bx+c, by computing the determinant, d=b24ac
If d<0, then there are no real roots.
If d=0, then there is one real root (called a repeated root).
If d>0, then there are two distinct real roots:
We have: 7x2+6x+3=0
d=624(7)(3)
d=120, therefore, there are two distinct real roots.

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