What is the equation of the line that passes through the points (-1, 3) and (1, 11)?

Rylee Friedman

Rylee Friedman

Answered question

2023-01-06

What is the equation of the line that passes through the points (-1, 3) and (1, 11)?

Answer & Explanation

Myncboyncgm6

Myncboyncgm6

Beginner2023-01-07Added 8 answers

The equation of a line in point-slope form is.
|22yy1=m(xx1)22|
where m represents the slope and (x1,y1)  a point on the line
To find m use the gradient formula
|22m=y2y1x2x122|
where (x1,y1),(x2,y2)  are 2 coordinate points
The 2 points here are  (1,3)  and  (1,11)
let  (x1,y1)=(1,3)  and  (x2,y2)=(1,11)
m=1131(1)=82=4
Use either of the 2 given points for  (x1,y1)
Using  m=4  and  (x1,y1)=(1,11)
y11=4(x1)  in point-slope form
An alternative formulation of the equation results from distribution and simplification.
y11=4x4
y=4x4+11
y=4x+7  in slope-intercept form

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