How to find the general form of the line passing through (-1,2) and (2,5)?

l1voyax

l1voyax

Answered question

2023-02-15

How to find the general form of the line passing through (-1,2) and (2,5)?

Answer & Explanation

levaretzf35

levaretzf35

Beginner2023-02-16Added 8 answers

Find the slope first. Input values for this equation to accomplish this.
m = y 2 - y 1 x 2 - x 1
m is the slope and the values are your original coords.
m = 5 - 2 2 - - 1
m = 3 3
m = 1
Now that we have the slope, we can utilize it to calculate the slope-intercept form and the y-intercept.
For this, we employ point-slope.
y - y 1 = m ( x - x 1 )
y - 2 = 1 ( x - - 1 )
y - 2 = ( x + 1 )
y - 2 = x + 1
y = x + 3
The slope is 1, and the y-intercept is 3. The slope-intercept form is "y=x+3", and the point-slope form is "y-2=1(x+1)"
Padehodarobxz6

Padehodarobxz6

Beginner2023-02-17Added 2 answers

the equation of a line in general form is.
| 2 2 A x + B y + C = 0 2 2 | ̲ ¯
where A is a positive integer and B, C are integers.
to begin express the equation in slope-intercept form
y = m x + b
where m represents the slope and b, the y-intercept
to calculate m use the gradient formula
| 2 2 m = y 2 - y 1 x 2 - x 1 2 2 | ̲ ¯
where ( x 1 , y 1 ) , ( x 2 , y 2 ) are 2 coordinate points
the points are ( x 1 , y 1 ) = ( - 1 , 2 ) , ( x 2 , y 2 ) = ( 2 , 5 )
m = 5 - 2 2 - ( - 1 ) = 3 3 = 1
y = x + b is the partial equation
to find b use either of the 2 given points
using ( 2 , 5 ) then
5 = 2 + b b = 3
y = x + 3 in slope-intercept form
x - y + 3 = 0 in general form

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