How to find a quadratic function whose vertex is at the point (2,9) and has the given x intercepts (1,0) & (3,0)?

Nathalie Dixon

Nathalie Dixon

Answered question

2023-02-13

How to find a quadratic function whose vertex is at the point (2,9) and has the given x intercepts (1,0) & (3,0)?

Answer & Explanation

chaghirun

chaghirun

Beginner2023-02-14Added 7 answers

Every quadratic function can be expressed in the standard form
f ( x ) = a x 2 + b x + c
In many Algebra textbooks, the preceding problem is rewritten using factoring and completing the square:
f ( x ) = a ( x - h ) 2 + k , where ( h , k ) is the vertex.
Because h = 2 and k = 9 , we can plug these into the rewritten f ( x ) to get:
f ( x ) = a ( x - 2 ) 2 + 9
The roots let us solve for a . The first root says f ( 1 ) = 0 and the second root says f ( 3 ) = 0 . Thus,
f ( 1 ) = a ( 1 - 2 ) 2 + 9 = 0 This gives a = - 9
f ( 3 ) = a ( 3 - 2 ) 2 + 9 = 0 . This also gives a = - 9
Hence f ( x ) = - 9 ( x - 2 ) 2 + 9 . To get the standard form, factor it out and make it simpler:
f ( x ) = - 9 x 2 + 36 x - 27

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