Check the solution to "x4(x2−3)6sin28x"

postillan4

Answered question

2021-01-06

x^{4} {(x^{2} - 3)}^{6} \sin^{2} 8 x

SabadisO

Skilled2021-01-07Added 108 answers

If the question is to find the zeros of the function, then here is the answer.
We have

x^{4} {(x^{2} - 3)}^{6} \sin^{2} 8 x = 0

only when

x^{4} = 0, or, x^{2} - 3)^{6} = 0, or, \sin^{2} 8 x = 0

This is equivalent to

x = 0, or, x^{2} - 3 = 0, or, \sin 8 x = 0

We know that sine function is zero for angles nπ,nπ, where nn is an integer. Therefore, we get

x = 0, or, x = \pm \sqrt{3}, or, x = \frac{8}{n π} .

If you need more explanation, or wanted something else then feel free to leave a comment. I will update the answer accordingly.

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