Solve the ¥ystem by clennaton2x-y=03x-2y=-3The solution is ( . )

Kye

Kye

Answered question

2021-06-16

Solve the system by clennaton 2xy=0
3x2y=3
The solution is ( . )

Answer & Explanation

unessodopunsep

unessodopunsep

Skilled2021-06-17Added 105 answers

The given system of equation is 2xy=0
3x2y=3
Multiply the equation (1) by 2 and subtract it from (2), that is, [(2)2x(1)] we get.
(3x2y)2(2xy)=32×03x2y2×(y)

=303x2y4x+2y=33x4x+=33x4x=3

x=3x=3
Now pluging the value of y in the equation (1) we get 23y=06y=0y=6
Hence the required solution (x,y)=(3,6)

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