Contain linear equations with constants in denominators. Solve each equation. (x+1)/4=1/6+(2-x)/3

Anish Buchanan

Anish Buchanan

Answered question

2021-05-14

Contain linear equations with constants in denominators. Solve each equation. x+14=16+2x3

Answer & Explanation

Adnaan Franks

Adnaan Franks

Skilled2021-05-15Added 92 answers

(x+1)3 = (1)2 + (2-x)4
_________________
12
(3x+3) = 2 + (8-4x)
(3x+3) = 10 - 4x
3 = 10 - 7x
(-7) = (-7x)
________
-7
The common denominator in this equation is 12.
Don't forget to FOIL.

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