preprekomW
2021-06-13
Jaylen Fountain
Skilled2021-06-15Added 169 answers
Ian Adams
Skilled2021-08-04Added 163 answers
Let x be the amount invested at 10%, yy be the amount invested at 7%, and z be the amount invested at 8%.
The total investment is $200000:
The annual income is $16,000:
The combined investment in alternatives 2 and 3 should be triple the amount invested in alternative 1 so:
or
Subtract each side of (1) and (3) then solve for xx:
Substitute x=50000 to (2) and simplify to obtain (4):
Substitute x=50000 to (1) and simplify to obtain (5):
Eliminate zz. Multiply (5) by 0.08 to obtain (6):
Subtract each side of (4) and (5) then solve for x:
Solve for zz using (5):
So, $50000 was invested at 10%, $100000 was invested at 7%, and $50000 was invested at 8%.
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V=??
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a)
b)
c)
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a.
b.
c.
d.
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,
,
,
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simplify
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