Find the equation of the quadratic function whose graph is

Burhan Hopper

Burhan Hopper

Answered question

2021-08-21

Find the equation of the quadratic function whose graph is a parabola containing the points(0.5), (4.41) and (-1.11)

Answer & Explanation

Malena

Malena

Skilled2021-08-22Added 83 answers

Let the quadratic equation be,
y=ax2+bx+c
Now this passes through the points (0.5),(4.41),(-1.11)
So we have : x=0, y=5
5=(a0)+(b0)+cc=5
x=4, y=41 41=(a4)+(b4)+c
=16a+4b+5
16a+4b=415=36
4a+b=9
x=1,y=1111=a(1)2+b(1)+c
ab=115=6
5a=15a=155=3
ab=6b=a6=36=3
Required equation is,

y=3x23x+5

Jeffrey Jordon

Jeffrey Jordon

Expert2022-01-14Added 2605 answers

Answer is given below (on video)

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