Reggie

2021-08-16

Write a quadratic equation in standard form with the given root(s). 1. 3, -4 2. -8,-2 3. 1,9 4. -5 5. 10,7 6. -2,15

Pohanginah

Skilled2021-08-17Added 96 answers

The roots of the quadratic equations are: 3 and -4

Hence, (x−3)and (x+4) are the factors of the quadratic equation.

Thus, the quadratic equation is given by:

(x−3)(x+4)=0

Solving it, we get:

${x}^{2}-3x+4x-12=0{x}^{2}+x-12=0$

Thus,${x}^{2}+x-12=0$ , is the standard form of the quadratic equation.

The roots of the quadratic equations are: -8 and -2

Hence, (x+8)and (x+2) are the factors of the quadratic equation.

The roots of the quadratic equations are: 1 and 9.

Hence, (x−1)and (x−9) are the factors of the quadratic equation.

Thus, the quadratic equation is given by:

(x−1)(x−9)=0

Solving it, we get:

${x}^{2}-9x-x+9=0{x}^{2}-10x+9=0$

Thus,${x}^{2}-10x+9=0$ , is the standard form of the quadratic equation.

Thus, the quadratic equation is given by:

(x+8)(x+2)=0

Solving it, we get:

${x}^{2}+2x+8x+16=0{x}^{2}+10x+16=0$

Thus,${x}^{2}10x+16=0$ , is the standard form of the quadratic equation.

Hence, (x−3)and (x+4) are the factors of the quadratic equation.

Thus, the quadratic equation is given by:

(x−3)(x+4)=0

Solving it, we get:

Thus,

The roots of the quadratic equations are: -8 and -2

Hence, (x+8)and (x+2) are the factors of the quadratic equation.

The roots of the quadratic equations are: 1 and 9.

Hence, (x−1)and (x−9) are the factors of the quadratic equation.

Thus, the quadratic equation is given by:

(x−1)(x−9)=0

Solving it, we get:

Thus,

Thus, the quadratic equation is given by:

(x+8)(x+2)=0

Solving it, we get:

Thus,

Nick Camelot

Skilled2023-05-27Added 164 answers

Mr Solver

Skilled2023-05-27Added 147 answers

madeleinejames20

Skilled2023-05-27Added 165 answers

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