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2021-09-13

The toll rates for crossing a bridge are $6.50 for a car and$10 for a truck. During a two-hour period, a total of 187 cars and trucks crossed the bridge, and the total collected in tolls was $1,338. Solving which of the following systems of equations yields the number of cars, x, and the number of trucks, y, that crossed the bridge during the two hours? A. $x+y=1,338$ $6.5x+10y=187$ B. $x+y=187$ $6.5x+10y=\frac{1,338}{2}$ C. $x+y=187$ $6.5x+10y=1,338$ D. $x+y=187$ $6.5x+10y=1,338×2$ ### Answer & Explanation SkladanH Skilled2021-09-14Added 80 answers let number of cars, x and number of trucks ,y that Crossed the bridge during the two hours. If x is number of cars crossed the bridge during the two hours and y that Crossed the bridge during the two hours. Then total number of car & tracks Cressed the bridge during the two hours Is, x+y Is equal to 187. x+y = 187 Similarily, The toll rates for Crossing a bridge are 6.50x for a car & 10y a trucks, I's equal to collected toll 1338$, $6.5x+10y=1338$ Hence,

Cotrect option Is

(c) $x+y=187$

$6.5x+10y=1338$

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