solve each problem by setting up and solving an appropriate system of equations. A motel in a suburb of Chicago rents double rooms for $120 per day and single rooms for $90 per day. If a total of 55 rooms were rented for $6150, how many of each kind were rented?

Question

solve each problem by setting up and solving an appropriate system of equations.   A motel in a suburb of Chicago rents double rooms for $120 per day and single rooms for $90 per day. If a total of 55 rooms were rented for $6150, how many of each kind were rented?

Arnold Odonnell · Accepted Answer

A motel in a suburb of Chicago rents double rooms for $120 per day and single rooms for $90 per day and total of 55 rooms were rented for $6150. Let x &amp;amp; y be the number of double rooms and single rooms respectively. Then, x+y=55→(1)  120x+90y=6150→(2) Now, [120·Equation (1)]−[Equation (2)]  ⇒120(x+y)−(120x+90y)=120(55)−6150⇒120x+120y−120x−90y=6600−6150⇒30y=450  ⇒y=15 Now put y=15 in equation (1), we get ⇒x+15=55⇒x=40 Hence 40 double rooms and 15 single rooms were rented.

A motel in a suburb of Chicago rents double rooms for $120 per day and single rooms for $90 per day.how many of each kind were rented?

Answered question

Answer & Explanation

New Questions in Algebra I