Find the distance between the pair of points (0,2) and (7,0). If necessary, express answers in simplified radical form and then round to two decimals places.

Given: The pair of points (0,−2) and (7,0) If (x1,y1) and (x2,y2) are two points in the x-y plane. then the following expression can be used to calculated the distance between them. d=(x2−x1)2+(y2−y1)2 d=distance (x1,x2)= coordinates of the first point (y1,y2)= coordinates of the second point d=(x2−x1)2+(y2−y1)2 d=(7−0)2+(0−(−2))2 d=(7)2+(2)2 d=7+2 d=9 d=3 unit the distance between the pair of points (0,−2) and (7,0) is 3 unit.

Explained: "Find the distance between the pair of points..."

High School
Algebra
Algebra I
Exponents and radicals

ringearV

Answered question

2021-09-16

Find the distance between the pair of points

(0, \sqrt{2})

and

(\sqrt{7}, 0)

. If necessary, express answers in simplified radical form and then round to two decimals places.

Answer & Explanation

Viktor Wiley

Skilled2021-09-17Added 84 answers

Given:
The pair of points

(0, - \sqrt{2})

and

(\sqrt{7}, 0)

(x_{1}, y_{1})

and

(x_{2}, y_{2})

are two points in the x-y plane. then the following expression can be used to calculated the distance between them.

d = \sqrt{{(x_{2} - x_{1})}^{2} + {(y_{2} - y_{1})}^{2}}

d=distance

(x_{1}, x_{2}) =

coordinates of the first point

(y_{1}, y_{2}) =

coordinates of the second point

d = \sqrt{{(x_{2} - x_{1})}^{2} + {(y_{2} - y_{1})}^{2}}

d = \sqrt{{(\sqrt{7} - 0)}^{2} + {(0 - (- \sqrt{2}))}^{2}}

d = \sqrt{{(\sqrt{7})}^{2} + {(\sqrt{2})}^{2}}

d = \sqrt{7 + 2}

d = \sqrt{9}

d = 3

unit
the distance between the pair of points

(0, - \sqrt{2})

and

(\sqrt{7}, 0)

is 3 unit.

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