Find an expression for the function whose graph is the given curve. The line segment joining the points (−5,10) and (7,10)

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cheekabooy · Accepted Answer

Equation of the line passing through (x1,y1) and (x2,y2) is y−y1x−x1=y2−y1x2−x1 Equation of the line passing through (−5,10) and (7,10) is y−10x−(−5)=−10−107−(−5) y−10x+5=−2012 y−5x+5=−53 Multiply both sides by x+5 y−10=−53x−253 Add 10 to both sides y−10+10=−53x−253+303 y=−53x+53 Note that is this equation of the line, to get the equation of the line segment include the limits on x y=−53x+53

alenahelenash · Accepted Answer

To find an expression for the function whose graph is the line segment joining the points (-5,10) and (7,10), we can start by noting that the function is a horizontal line since the y-coordinates of both points are the same (10).Let&#039;s denote the function as f(x). Since the line is horizontal, the value of f(x) is constant for all values of x. In this case, f(x)=10 for any x within the interval [-5, 7].Therefore, the expression for the function can be written as:f(x)=10

star233 · Accepted Answer

Step 1:The slope of a line passing through two points (x₁, y₁) and (x₂, y₂) is given by the formula:m=y₂−y₁x₂−x₁Using the coordinates of the given points (-5, 10) and (7, 10), we can calculate the slope:m=10−107−(−5)=012=0Step 2:Since the slope is 0, we know that the line is a horizontal line. A horizontal line has the same y-coordinate for all points along its length.Therefore, the equation of the line can be written as:y=cwhere c is a constant representing the y-coordinate of any point on the line.In this case, since the y-coordinate is always 10, we can rewrite the equation as:y=10Thus, the expression for the function whose graph is the given line segment is y=10.

karton · Accepted Answer

Result:y=10Solution:We&#039;ll use the point-slope form of the equation of a line, which is given by:y−y1=m(x−x1)where (x1,y1) are the coordinates of one point on the line, and m is the slope of the line.First, let&#039;s calculate the slope of the line using the formula:m=y2−y1x2−x1In this case, (x1,y1)=(−5,10) and (x2,y2)=(7,10). Substituting these values into the slope formula, we get:m=10−107−(−5)=012=0Since the slope of the line is zero, the line is horizontal. We know that any horizontal line can be expressed as y=c, where c is a constant. In this case, the constant value is 10, as it represents the y-coordinate of the line.Therefore, the expression for the function whose graph is the line segment joining the points (-5, 10) and (7, 10) can be written as:y=10The graph of this function is a horizontal line at the y-coordinate 10, as desired.

Find an expression for the function whose graph is the given curve. The line seg

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