Find, to the nearest tenth of a second, the period of a pendulum of length 3.5 feet.

Question

Asma Vang · Accepted Answer

Given:
To calculated period of pendulums of the given lengths are 2 feet, 3 feet and 4,5 feet.
Coefficient of friction is 0.4
Formula:

T = 2 π \sqrt{\frac{L}{32}}

where L is the length of period of the pendulum.
Calculating the period of pendulum of length 2 feet :

T = 2 (3.14) \sqrt{\frac{2}{32}}

= 2 (3.14) \sqrt{0.0625}

Taking square root,

T = 2 (3.14) (0.25)

= 1.57

= 1.6

seconds
Calculating period of pendulum of length 3 feet.

T = 2 (3.14) \sqrt{\frac{3}{32}}

= 2 (3.14) (0.31)

= 1.9468

= 1.9

seconds
Calculating period of pendulum of length 4.5 feet:

t = 2 (3.14) \sqrt{\frac{4.5}{3.2}}

= 2 (3.14) \sqrt{0.140625}

= 2 (3.14) (0.375)

= 2.355

= 2.4

seconds
Therefore, the periods of pendulum of lengths 2 feet, 3 feet, 4.5 feet are 1.6 seconds, 1.9 seconds, and 2.4 seconds respectively.

Find, to the nearest tenth of a second, the period of a pendulum of length 3.5 f