Mathematic

Answered question

2021-10-28

Use factor formula to show that sin5a+sin2asina=sin2a(2cos3a+1)

Answer & Explanation

Jeffrey Jordon

Jeffrey Jordon

Expert2021-11-10Added 2605 answers

Step 1

Given: sin5AsinA+sin2A=sin2A(2cos3A+1)

sin5AsinA+sin2A=2sin2Acos3A+sin2A

Since both sides have sin2A

sin5AsinA=2sin2Acos3A.

sinusinv=2cos(u+v2)sin((uv2))

=2cos5A+A2sin5AA2+sin2A

=2cos6A2sin4A2+sin2A

=2cos3Asin2A+sin2A

=sin2A(2cos3A+1)

Factor out sin2A

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