Find the Equation of a quadratic function whose graph is parabola passing throug

ankarskogC

ankarskogC

Answered question

2021-11-06

Find the Equation of a quadratic function whose graph is parabola passing through the point.
(2,9), (2,7) and (4,9)

Answer & Explanation

Ezra Herbert

Ezra Herbert

Skilled2021-11-07Added 99 answers

Given
Points A=(2,9)
B=(2,7)
C=(4,9)
W.k.t equation of parabola is
y=ax2+bx+c
Substitute A=(2,9)
9=a(2)2+b(2)+c
9=4a2b+c
4a2b+c=9..........(1)
y=ax2+bx+c Substitute B=(2,7)
7=a(2)2+b(2)+c
7=4a+2b+c
4a+2b+c=7..........(2)
y=ax2+bx+c
Substitute C=(4,9)
9=a(4)2+b(4)+c
9=16a+4b+c
16a+4b+c=9..........(3)
Solving (1) and (2)
4a2b+c=9 ()4a+()2b+()c=()74b=16
b=164
b=4
solving (2) and (3)
4a+2b+c=7 ()16a+()4b+()c=(+)912a2b=16
6a+b=8
Substitute b=4
6a+b=8
6a+4=8
6a=12
a=126
a=2
Substitute a=2 and b=4 in (1)
4a2b+c=9
4(2)2(4)+c=9
88+c=9
16+c=9
c=7
substitute the value a=2,

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