Solve 3y^{2}-72=0, where y is a real number.

SchachtN

SchachtN

Answered question

2021-11-06

Solve 3y272=0, where y is a real number.

Answer & Explanation

liannemdh

liannemdh

Skilled2021-11-07Added 106 answers

Step 1
Given: 3y272=0
So: 3y2=72
y2=723=24
Than: y=±24
y=±26
So, there are 2 Solution of Given quadratic equation
y=+26, 26

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