The function, f(x)=−2x2+x+5, is in standard form. The quadratic equation is 0=−2x2+x+5, where a=−2, b=1, and c=5. The discriminate b2−4ac is 41. Now, complete step 5 to solve for the zeros of the quadratic function. Solve using the quadratic formula. x=−b±b2−4ax2a What are the zeros of the function f(x)=x+5−2x2? a) x=−1±41−4 b) x=1±41−4 c) x=−1±39−4 d) x=1±39−4

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The function, f(x)=−2x2+x+5, is in standard form. The quadratic equation is 0=−2x2+x+5, where a=−2, b=1, and c=5. The discriminate b2−4ac is 41. Now, complete step 5 to solve for the zeros of the quadratic function.  Solve using the quadratic formula.  x=−b±b2−4ax2a  What are the zeros of the function  f(x)=x+5−2x2?  a) x=−1±41−4  b) x=1±41−4  c) x=−1±39−4  d) x=1±39−4

Keith Dooley · Accepted Answer

Step 1  f(x)=x+5−2x2  a=−2×b=1, c=5  x=−b±b2−4ac2a=−1±1−4×−2×52(−2)  =−1±1+40−4=−1±41−4  x1=−1+41−4  x2=−1−41−4  x=−1±41−4

The function, f(x)=-2x^{2}+x+5, is in standard form. The quadratic equation

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