Find the coordinates of the x-intercepts of the graph of

luipieduq3

luipieduq3

Answered question

2021-12-03

Find the coordinates of the x-intercepts of the graph of the equation. (If an answer does not exist, enter DNE.)
y=x24x11
(x,y)=
Find the minimum or maximum value of the quadratic function.
f(x)=4x2+8x6 --Select— minimum value maximum value
f(x)=

Answer & Explanation

George Blue

George Blue

Beginner2021-12-04Added 18 answers

Step 1
The given equation is,
y=x24x11
From the graph it is clear that the x — intercepts (a,0) of the function does not exists.
That is,
x24x11=0
x=(4)±(4)24(1)(11)2
=27i
Which is imaginary.
Therefore the answer is DNE.
The maximum or minimum value of the quadratic function is obtained as follows.
4x2+8x6=0 which is of the form ax2+bx+c=0
As a<0, the parabola opens downwards and we find the maximum value.
x=b2a
=82(4)
=1
f(1)=4(1)2+8(1)6
=2
The maximum value is (1,2)

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