Given that f(x)=3x-2g(x)=4x+6\ and\ h(x)=2x^{2}-8x Find: i) f(-5)= ii) h [f(2)]= iii)

grasaladae5

grasaladae5

Answered question

2021-12-04

Given that f(x)=3x2g(x)=4x+6 and h(x)=2x28x
Find: i) f(5)=
ii) h[f(2)]=
iii) f[g(1)]=i
iv) h of(x)
v) =g1(x)

Answer & Explanation

SaurbHurbkj

SaurbHurbkj

Beginner2021-12-05Added 16 answers

Given
f(x)=3x2,g(x)=4x+6,h(x)=2x20
So f:-
(i)f(5)=3(5)2
=152
=17.
(ii)h[f(2(]=h[3(2)]
=h[62]
h[4]
=2(4)28
2×168
328
=24
(iii)f[g(1)]=f[4(1)+6]
=f[4+6]
=f[2]
3×22
=62
=4.
i(v)h of(x)=h[f(x)]
=2(3x2)28
=2[9x2+412x]8
=18x2+824x8
=18x224x
(iv)g1(x)=?
g(x)=4x+6
ies y=4x+6
Switch x and y
((because even (z,y) has a ((y,x) pentner)
x=4y+6
4y=x6
y=1x464
y=1x432
g1(x)=1x432

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