Use the discriminant, b2−4ac, to determine the number of solutions of the following quadratic equation. Then solve the quadratic equation using the quadratic formula. −6x2−5=2 Select the number and type of solutions. Then, enter the solutions. a) Two different real solutions b) One Repeated real solution c) Two Non-Real solutions.

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Use the discriminant, b2−4ac, to determine the number of solutions of the following quadratic equation. Then solve the quadratic equation using the  quadratic formula.  −6x2−5=2  Select the number and type of solutions. Then, enter the solutions.  a) Two different real solutions  b) One Repeated real solution  c) Two Non-Real solutions.

Louise Eldridge · Accepted Answer

Step 1  Given equation  −6x2−5x=2  1) ⇒6x2+5x+2=0  Step 2  Using the discriminant  If b2−4ac&amp;gt;0 then equation has two different real solution  If b2−4ac&amp;lt;0 then equation has complex solution  If b2−4ac=0 then equation has one repeated real solution  Step 3  Now equation (1) comparing ax2+bx+c=0  a=6, b=5 and c=2  Discriminant =b2−4ac  =52−4(6)(2)  =25−48  =−23&amp;lt;0  ⇒ Given equation has complex solution.  ⇒ Given equation has two non real solution  Option (C) is correct  Therefore,  x=−b±b2−4ac2a  x=−5±−232(6)  x=−5±i2312  x=−5+i2312, −5−i2312  It is two non real solution

Use the discriminant, b2−4ac, to determine the number of solutions

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