The tolerance for a ball bearing is 0.01. If the true diameter of the bearing is to be 2.0 inches and the measured value of the diameter is x inches, express the tolerance using absolute value notation.

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Wriedge · Accepted Answer

Given:  The tolerance is 0.01 and the diameter of bearing is 2 inches.  Calculation:  The diameter is expressed in x.  The tolerance is 0.01 and the diameter is 2 inches.  So,|x—2|≤0.01  Conclusion:  Thus, the absolute value notation for the given statement is |x — 2| &amp;lt; 0.01

Andre BalkonE · Accepted Answer

Result:|x−2.0|≤0.01Solution:Let x represent the measured value of the diameter in inches. The absolute difference between x and the true value of 2.0 inches is given by |x−2.0|.Since the tolerance for the ball bearing is 0.01 inches, we want to ensure that the absolute difference between the measured value and the true value is less than or equal to 0.01 inches.Therefore, the tolerance can be expressed using absolute value notation as:|x−2.0|≤0.01

fudzisako · Accepted Answer

Step 1: Let&#039;s denote the true diameter of the bearing as Dtrue and the measured diameter as x. The tolerance, denoted as T, can be expressed using absolute value notation as follows:T=|x−Dtrue|In this case, the true diameter is given as 2.0 inches. Substituting this value into the equation, we have:T=|x−2.0|The tolerance T represents the acceptable range of values for the diameter of the ball bearing, centered around the true diameter of 2.0 inches. If the absolute value of the difference |x−2.0| is less than or equal to 0.01, then the measured value falls within the tolerance.For example, if x=2.01 inches, then the tolerance would be:T=|2.01−2.0|=0.01&amp;nbsp;inchesStep 2: Since the absolute value of the difference is equal to the tolerance, the measured value of 2.01 inches is within the acceptable range.Similarly, if x=1.98 inches, the tolerance would be:T=|1.98−2.0|=0.02&amp;nbsp;inchesIn this case, the absolute value of the difference is greater than the tolerance, indicating that the measured value of 1.98 inches falls outside the acceptable range.By expressing the tolerance using absolute value notation, we can easily determine whether a measured value is within the acceptable range of the ball bearing&#039;s diameter.

xleb123 · Accepted Answer

To express the tolerance using absolute value notation, we can use the following equation:|x−2.0|=0.01Here, x represents the measured value of the diameter, and 2.0 represents the true diameter of the bearing. The absolute value |x−2.0| ensures that the difference between the measured value and the true value is within the tolerance of 0.01 inches.

The tolerance for a ball bearing is 0.01. If the

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