Consider the function f(x)=1-6x^{2}, -4\le x\le 2. The absolute maximum value

tornesasln

tornesasln

Answered question

2021-12-06

Consider the function f(x)=16x2,4x2.
The absolute maximum value is and this occurs at x =?
The absolute minimum value is and this occurs at x=?

Answer & Explanation

Parminquale

Parminquale

Beginner2021-12-07Added 17 answers

Step 1: Concept/formula
ddxxn=nxn1
Step 2: Solution
f(x)=16x2
f(x)=06(2)x21
f'(x)=-12x
Critical number
-12x=0
x=0
Finding the values of the function at the boundary points and critical value.
f(4)=16(4)2=95
f(0)=16(0)2=1
f(2)=16(2)2=23
Maximum is at x=0 which is 1.Absolute maximum is 1 at x=0
Minimum is at x=-4 which is -95. Absolute minimum is -95 at x=-4

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?