Consider the function f(x)=1-4x^{2}, -5\le x\le 2. The absolute maximum value

killjoy1990xb9

killjoy1990xb9

Answered question

2021-12-13

Consider the function f(x)=14x2,5x2.
The absolute maximum value is
and this occurs at x=
The absolute minimum value is
and this occurs at x=

Answer & Explanation

David Clayton

David Clayton

Beginner2021-12-14Added 36 answers

Step 1
Let f(x)=14x2,5x2
identifying important points
f'(x)=0
8x=0
x=0
Step 2
Finding values of f(x) at x=0, x=-5 and x=2
f(0)=14(0)2=1 maximum value
f(5)=14(5)2=99 minimum value
f(2)=14(2)2=15
Consequently, 1 is the absolute maximum value, which is reached at x=0.
At x=-5, the absolute minimum value, which is -99, is reached.

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