Consider the function f(x)=4−6x2, −4≤x≤2. The absolute maximum value is B⊗ and this occurs at x= B⊗ The absolute minimum value is B⊗ and this occurs at x= B⊗

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Consider the function f(x)=4−6x2,   −4≤x≤2.  The absolute maximum value is B⊗  and this occurs at x= B⊗  The absolute minimum value is B⊗  and this occurs at x= B⊗

ramirezhereva · Accepted Answer

Step 1Given:The functionf(x)=4−6x2,−4≤x≤2Step 2First calculate the critical point by differentiate f(x)=4−6x2, and equate it to zero.f′(x)=ddx(4−6x2)=-12xSet f&#039;(x)=0-12x=0x=0Thus the critical point is x=0At x=0 the value of f(x)=4−6x2 isf(0)=4−6(0)2f(0)=4...(1)Step 3Now find the value of f(x)=4−6x2 at the endpoints −4≤x≤2At x=-4f(−4)=4−6(−4)2=4-96f(-4)=-92...(2)At x=2f(2)=4−6(2)2=4-24f(-2)=-20...(3)By comparing (1),(2), and (3)The absolute maximum value is 4 and this occur at x=0The absolute minimum value is -92 and this occur at x=-4

Consider the function f(x)=4-6x^{2}, \ \ \ -4\le x\le 2. The

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