Solving Quadratics by Squore Roots Digital Clue 1) x2=8 2) x2=−5 3) −2x2=−42 4) 25x2=16 5) −4x2=48

Question

Solving Quadratics by Squore Roots Digital Clue  1) x2=8  2) x2=−5  3) −2x2=−42  4) 25x2=16  5) −4x2=48

hysgubwyri3 · Accepted Answer

Step 1  Given: x2=8  ⇒x=8  ⇒x=2×2×2  =x=22  Step 2  Given: x2=−5  ⇒x2=+5i2  (i2=−1)  ⇒x=5i2  ⇒x=i5  Step 3  Given: −2x2=−42  Divide both side by -2  ⇒−2x2−2=−42−2  ⇒x2=21  ⇒x=21  Step 4  Given: 25x2=16  Divide both side by 25  ⇒25x225=1625  ⇒x2=1625  ⇒x=1625=±45  Step 5  Given: −4x2=48  Devide both side by -4  ⇒−4x2−4=48−4  ⇒x2=−12=12i2  =x=4×3×i2=23i

Jeffery Autrey · Accepted Answer

Step 1 1) x2=8 Subtract 8 from both sides. x2−8=0 This equation is in standard form: ax2+bx+c=0 Substitute 1 for a, 0 for b, and −8 for c in the quadratic formula, −b±b2−4ac2a x=0±02−4(−8)2 Square 0 x=0±−4(−8)2 Multiply -4 times -8. x=0±322 Take the square root of 32 x=0±422 Now solve the equation when ± is plus x=22 minus x=−22 Step 2 2) x2=−5 Add 5 to both sides x2+5=0 This is in standard form. Substitute 1 for a, 0 for b and 5 for c in the quadratic formula x=0±02−4×52 x=0±−4×52 Multiply -4 times 5 x=0±−202 Take the square root of -20 x=0±25i2 Now solve the equation is minus x=−5i plus x=5i Step 3 3) −2x2=−42 Divide both sodes by -2 x2=−42−2 Divide -42 by -2 to get 21 x2=21 Subtract 21 from both sides x2−21=0 Standatr form in the quadratic fromula x=0±02−4(−21)2 x=0±4(−21)2 Multiply -4 times -21 x=0±842 Take the square root of 84 x=0±2212 Solve the equation is plus and minus x=21 x=−21 Step 4 4) 25x2=16 Divide both sides by 25 x2=1625 Subtract 1625 from both sides x−1625=0 x=0±02−4(−1625)2

Solving Quadratics by Squore Roots Digital Clue 1) x^{2}=8 2) x^{2}=-5 3) -2x^{2}=-42 4)

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