Use the point-slope formula and the given slope and point to find the linear equation in slope-intercept form.
M=1 and p=(4,3)
You want to find the equation for a line that passes through the point (4,3) and has a slope of 1.
First of all, remember what the equation of a line is:
y = mx+b
m is the slope, and
b is the y-intercept
To start, you know what m is; it's just the slope, which you said was 1. So you can right away fill in the equation for a line somewhat to read:
Now, what about b, the y-intercept?
To find b, think about what your (x,y) point means:
(4,3). When x of the line is 4, y of the line must be 3.
Because you said the line passes through this point, right?
Now, look at our line's equation so far: b is what we want, the 1 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (4,3).
(4,3). y=mx+b or 3=1 × 4+b, or solving for b: b=3-(1)(4). b=-1.
The equation of the line that passes through the point (4,3) with a slope of 1 is y=1x-1
Answer: A: y=x-1
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